Combustion Chemistry Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

easy
Balance the combustion of butane: C4H10+O2โ†’CO2+H2O\text{C}_4\text{H}_{10} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}.

Solution

  1. 1
    Balance C: 4 CO2\text{CO}_2. Balance H: 10 H โ†’ 5 H2O\text{H}_2\text{O}. O needed: 4(2)+5(1)=134(2) + 5(1) = 13 O atoms โ†’ 132O2\frac{13}{2}\text{O}_2.
  2. 2
    Multiply everything by 2: 2C4H10+13O2โ†’8CO2+10H2O2\text{C}_4\text{H}_{10} + 13\text{O}_2 \rightarrow 8\text{CO}_2 + 10\text{H}_2\text{O}.

Answer

2C4H10+13O2โ†’8CO2+10H2O2\text{C}_4\text{H}_{10} + 13\text{O}_2 \rightarrow 8\text{CO}_2 + 10\text{H}_2\text{O}
When balancing produces fractional coefficients, multiply all coefficients by the denominator to get whole numbers.

About Combustion

A rapid exothermic chemical reaction in which a fuel reacts with oxygen gas, releasing large amounts of energy as heat and light.

Learn more about Combustion โ†’

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