Balancing Equations Chemistry Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

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Balance: Al+HClโ†’AlCl3+H2\text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2.

Solution

  1. 1
    Balance Al: already 1 on each side. Balance Cl: 1 on left, 3 on right โ†’ put 3 before HCl.
  2. 2
    Now H: 3 on left, 2 on right. Use 6 HCl and 3 H2_2: 2Al+6HClโ†’2AlCl3+3H22\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2. Check: Al 2=2, H 6=6, Cl 6=6. โœ“

Answer

2Al+6HClโ†’2AlCl3+3H22\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2
When balancing creates fractional coefficients, multiply all coefficients by the smallest number that gives whole numbers.

About Balancing Equations

The process of adjusting the coefficients (the numbers placed before chemical formulas) in a chemical equation so that the number of atoms of each element.

Learn more about Balancing Equations โ†’

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