Experimental Probability Statistics Example 4

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Example 4

hard
A basketball player made 72 out of 100 free throws in practice. (a) What is her experimental free-throw probability? (b) In the next game, she attempts 15 free throws. How many would you expect her to make? (c) Why might the actual number differ from your prediction?

Solution

  1. 1
    Step 1: (a) P(make)=72100=0.72P(\text{make}) = \frac{72}{100} = 0.72. (b) Expected makes = 15ร—0.72=10.8โ‰ˆ1115 \times 0.72 = 10.8 \approx 11 free throws.
  2. 2
    Step 2: (c) The actual number may differ because: (1) 15 attempts is a small sample size with high variability, (2) game pressure differs from practice, (3) experimental probability is an estimate and individual attempts are independent random events.

Answer

(a) P=0.72P = 0.72. (b) Expected: about 11 free throws. (c) Small sample size, game pressure, and randomness may cause the actual result to differ.
Experimental probability provides estimates useful for prediction, but predictions are uncertain, especially with small sample sizes. Real-world factors (pressure, fatigue) may also cause actual performance to deviate from practice-based estimates.

About Experimental Probability

Experimental probability is the probability of an event estimated from actual experimental data, calculated as the number of times the event occurred divided by the total number of trials. It approaches the theoretical probability as more trials are conducted.

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