Experimental Probability Statistics Example 3

Solution

1. 1
   Step 1: (a) $P(R) = \frac{45}{120} = 0.375$, $P(B) = \frac{50}{120} \approx 0.417$, $P(G) = \frac{25}{120} \approx 0.208$.
2. 2
   Step 2: (b) If the spinner were fair (3 equal sections), each probability would be $\frac{1}{3} \approx 0.333$. Green's probability (0.208) is noticeably lower, suggesting the spinner is likely not fair — the green section may be smaller.