Work Physics Example 3

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Example 3

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A 5 kg5 \text{ kg} box is lifted 3 m3 \text{ m} vertically at constant speed. How much work is done by the lifting force? Use g=9.8 m/s2g = 9.8 \text{ m/s}^2.

Solution

  1. 1
    At constant speed, the lifting force equals the weight: F=mg=5×9.8=49 NF = mg = 5 \times 9.8 = 49 \text{ N}.
  2. 2
    Work: W=Fd=49×3=147 JW = Fd = 49 \times 3 = 147 \text{ J}

Answer

W=147 JW = 147 \text{ J}
Lifting an object at constant speed requires a force equal to its weight. The work done equals the gain in gravitational potential energy.

About Work

The transfer of energy that occurs when a force causes an object to move through a distance in the direction of the force, calculated as.

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