Work Physics Example 2

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Example 2

medium
A person pulls a sled with 100 N100 \text{ N} at 30°30° above the horizontal for 20 m20 \text{ m}. How much work is done?

Solution

  1. 1
    Because the force is angled, use the component along the displacement: W=FdcosθW = Fd\cos\theta.
  2. 2
    Substitute the values: W=100×20×cos30°=2000×0.866W = 100 \times 20 \times \cos 30° = 2000 \times 0.866.
  3. 3
    W=1732 JW = 1732 \text{ J}

Answer

W1732 JW \approx 1732 \text{ J}
When the force is at an angle to the displacement, only the component of force along the displacement does work. The cosine factor accounts for this.

About Work

The transfer of energy that occurs when a force causes an object to move through a distance in the direction of the force, calculated as.

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