Wavelength Physics Example 4

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Example 4

medium
A sound wave has frequency 440 Hz and travels at 343 m/s. Find the wavelength.

Solution

  1. 1
    Use the wave equation relating speed, frequency, and wavelength: v=fฮปv = f\lambda.
  2. 2
    Rearrange to solve for wavelength: ฮป=vf\lambda = \frac{v}{f}.
  3. 3
    Substitute the values: ฮป=343โ€‰m/s440โ€‰Hz=0.780โ€‰m\lambda = \frac{343\,\text{m/s}}{440\,\text{Hz}} = 0.780\,\text{m}

Answer

The wavelength is ฮปโ‰ˆ0.780โ€‰m\lambda \approx 0.780\,\text{m} (about 78 cm).
The note A4 (440 Hz) is the standard tuning pitch. At the speed of sound in air (343 m/s at 20\u00b0C), its wavelength is about 78 cm. Higher-frequency sounds have shorter wavelengths, and lower-frequency sounds have longer wavelengths.

About Wavelength

Wavelength is the distance between two consecutive identical points on a wave, such as from one peak to the next peak or one trough to.

Learn more about Wavelength โ†’

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