Transverse Wave Physics Example 4

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Example 4

hard
A guitar string (μ=0.003 kg/m\mu = 0.003 \text{ kg/m}, length 0.65 m0.65 \text{ m}) is tuned to play a note at 330 Hz330 \text{ Hz} (fundamental mode). What tension must be applied to the string?

Solution

  1. 1
    In the fundamental mode, the string vibrates with a wavelength λ=2L=2×0.65=1.3 m\lambda = 2L = 2 \times 0.65 = 1.3 \text{ m}.
  2. 2
    Wave speed: v=fλ=330×1.3=429 m/sv = f\lambda = 330 \times 1.3 = 429 \text{ m/s}.
  3. 3
    Tension: T=μv2=0.003×4292=0.003×184041552 NT = \mu v^2 = 0.003 \times 429^2 = 0.003 \times 184041 \approx 552 \text{ N}.

Answer

T552 NT \approx 552 \text{ N}
Musical instruments rely on transverse standing waves. The tension must be precisely set to produce the desired frequency. Higher tension gives higher pitch for the same string length and density.

About Transverse Wave

A wave in which the particles of the medium oscillate perpendicular to the direction of wave propagation.

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