Spring Force Physics Example 5

Solution

1. 1
   In series, the same force acts on each spring. Extension of spring 1: $x_1 = \frac{F}{k_1} = \frac{12}{200} = 0.06 \text{ m}$.
2. 2
   Extension of spring 2: $x_2 = \frac{F}{k_2} = \frac{12}{300} = 0.04 \text{ m}$.
3. 3
   Total extension: $x_{\text{total}} = x_1 + x_2 = 0.06 + 0.04 = 0.10 \text{ m}$. (Equivalent $k_{\text{eff}} = \frac{F}{x} = \frac{12}{0.1} = 120 \text{ N/m}$.)