Speed Physics Example 3

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Example 3

medium
A train travels 120 km120 \text{ km} at 60 km/h60 \text{ km/h} and then 120 km120 \text{ km} at 40 km/h40 \text{ km/h}. What is the average speed for the whole trip?

Solution

  1. 1
    Time for first part: t1=12060=2 ht_1 = \frac{120}{60} = 2 \text{ h}.
  2. 2
    Time for second part: t2=12040=3 ht_2 = \frac{120}{40} = 3 \text{ h}.
  3. 3
    Average speed: savg=total distancetotal time=2405=48 km/hs_{\text{avg}} = \frac{\text{total distance}}{\text{total time}} = \frac{240}{5} = 48 \text{ km/h}

Answer

savg=48 km/hs_{\text{avg}} = 48 \text{ km/h}
Average speed is not simply the arithmetic mean of two speeds. It is total distance divided by total time. Spending more time at the lower speed pulls the average below 50 km/h50 \text{ km/h}.

About Speed

The rate at which an object covers distance over time, calculated as total distance divided by total time, always expressed as a non-negative scalar quantity.

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