Potential Energy Physics Example 3

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Example 3

medium
A 0.3 kg0.3 \text{ kg} ball on a compressed spring (k=800 N/mk = 800 \text{ N/m}, compressed 0.15 m0.15 \text{ m}) is released. What speed does the ball reach?

Solution

  1. 1
    Spring PE: PE=12kx2=12(800)(0.0225)=9 JPE = \frac{1}{2}kx^2 = \frac{1}{2}(800)(0.0225) = 9 \text{ J}.
  2. 2
    This converts entirely to KE: 12mv2=9\frac{1}{2}mv^2 = 9.
  3. 3
    v=2×90.3=607.75 m/sv = \sqrt{\frac{2 \times 9}{0.3}} = \sqrt{60} \approx 7.75 \text{ m/s}

Answer

v7.75 m/sv \approx 7.75 \text{ m/s}
When a compressed spring releases, its elastic PE converts to kinetic energy. Conservation of energy lets us find the speed without knowing the details of the force during release.

About Potential Energy

Energy stored in a system due to the position or configuration of its parts, ready to be converted into kinetic or other forms of energy.

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