Position Physics Example 3

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Example 3

medium
An ant walks from position x=5 mx = -5 \text{ m} to x=7 mx = 7 \text{ m}, then back to x=2 mx = 2 \text{ m}. What is the total distance traveled and the final displacement from the starting point?

Solution

  1. 1
    Distance from 5-5 to 77: 7(5)=12 m|7 - (-5)| = 12 \text{ m}. Distance from 77 to 22: 27=5 m|2 - 7| = 5 \text{ m}. Total distance: 12+5=17 m12 + 5 = 17 \text{ m}.
  2. 2
    Displacement: Δx=xfxi=2(5)=7 m\Delta x = x_f - x_i = 2 - (-5) = 7 \text{ m} in the positive direction.

Answer

Distance=17 m,Displacement=7 m\text{Distance} = 17 \text{ m}, \quad \text{Displacement} = 7 \text{ m}
Total distance counts all ground covered regardless of direction, while displacement only depends on the starting and ending positions. This distinction is fundamental in kinematics.

About Position

The location of an object relative to a chosen reference point (origin), described using coordinates in a given reference frame.

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