Read the first worked example with the solution open so the structure is clear.
Try the practice problems before revealing each solution.
Use the related concepts and background knowledge badges if you feel stuck.
What to Focus On
Core idea:Photoelectric Effect asks whether the system is nuclear, quantum, or relativistic before using an everyday model.
Common stuck point:Students often know a formula related to photoelectric effect but skip the recognition step: Does the situation involve particles, nuclei, photons, or relativistic speeds where everyday mechanics is not enough? That leads to a correct-looking substitution attached to the wrong physical model.
Sense of Study hint:Ask: Does the situation involve particles, nuclei, photons, or relativistic speeds where everyday mechanics is not enough?
Worked Examples
Example 1
medium
A photon of frequency 1.0×1015 Hz strikes sodium (ϕ=3.65×10−19 J). Find KEmax. (h=6.6×10−34)
Answer
KEmax≈2.95×10−19 J
First step
1
Ephoton=hf=(6.6×10−34)(1.0×1015)=6.6×10−19 J.
See the full worked solution + why-it-works coaching
Setup·Key insight·Why it works·Common pitfall·Connection
A photon of wavelength 300 nm strikes a metal with ϕ=3.0×10−19 J. Find KEmax. (h=6.6×10−34, c=3×108)
Example 3
medium
A photon of E=5.0 eV hits a metal with ϕ=2.0 eV. Find KEmax in joules (1 eV=1.6×10−19 J).
Example 4
hard
A photon of frequency 1.5×1015 Hz ejects an electron from a metal of ϕ=4.0×10−19 J. Find the electron's maximum speed (h=6.6×10−34, me=9.1×10−31 kg).
Example 5
hard
Light of frequency 2f0 hits a metal with threshold f0. Express KEmax in terms of ϕ.
Example 6
challenge
In a Millikan-style experiment, stopping voltages are V1=0.5 V at f1=5×1014 Hz and V2=1.5 V at f2=7.5×1014 Hz. Find Planck's constant. (e=1.6×10−19 C)
Practice Problems
Try these problems on your own first, then open the solution to compare your method.
Example 1
easy
Find the energy of a photon of frequency f=5×1014 Hz. (h=6.6×10−34)
Example 2
easy
In the photoelectric effect, electrons are emitted only when light has a high enough what?
Example 3
easy
Write the photoelectric equation relating photon energy, work function, and maximum kinetic energy.
Example 4
easy
If a metal's work function is ϕ=3×10−19 J and a photon delivers 5×10−19 J, find the maximum kinetic energy of the electron.
Example 5
easy
Does increasing the brightness (intensity) of light below the threshold frequency cause electron emission?
Example 6
easy
Above the threshold, does increasing intensity increase the number or the energy of emitted electrons?
Example 7
easy
Find the threshold frequency for a metal with work function ϕ=3.3×10−19 J. (h=6.6×10−34)
Example 8
easy
In the photoelectric effect, light behaves more like a wave or like particles (photons)?
Example 9
medium
A photon of frequency 8×1014 Hz hits a metal with work function 3.3×10−19 J. Find KEmax. (h=6.6×10−34)
Example 10
medium
A metal has threshold frequency 4×1014 Hz. Find its work function. (h=6.6×10−34)
Example 11
medium
The stopping potential for ejected electrons is 1.5 V. Find their maximum kinetic energy (e=1.6×10−19 C).
Example 12
medium
A photon has wavelength λ=4×10−7 m. Find its energy. (h=6.6×10−34, c=3×108)
Example 13
medium
Light of energy 6×10−19 J ejects electrons with KEmax=2×10−19 J. Find the work function.
Example 14
medium
Two metals have work functions ϕ1=2×10−19 and ϕ2=5×10−19 J. For the same photon energy, which emits faster electrons?
Example 15
medium
A photon of frequency 6imes1014extHz hits a metal with work function 2.6imes10−19extJ. Find KEmax. (h=6.6imes10−34)
Example 16
medium
A metal emits electrons with KEmax=1.4imes10−19extJ under a photon of 4imes10−19extJ. Find the work function.
Example 17
medium
The stopping potential is 2extV. Find the maximum kinetic energy of the electrons (e=1.6imes10−19extC).
Example 18
challenge
A photon of 7×10−19 J hits a metal with ϕ=4×10−19 J. Find the electron's maximum speed (me=9.1×10−31 kg).
Example 19
challenge
Light of wavelength 3×10−7 m strikes a metal with work function 4×10−19 J. Find KEmax. (h=6.6×10−34, c=3×108)
Example 20
challenge
Photon energy E just exceeds work function ϕ so KEmax=0.1ϕ. Express E in terms of ϕ.
Example 21
easy
Find the energy of a photon with frequency f=6×1014 Hz. (h=6.6×10−34)
Example 22
easy
The work function of a metal is 4.5×10−19 J. Find its threshold frequency. (h=6.6×10−34)
Example 23
easy
A metal has ϕ=3.0×10−19 J. A photon arrives with E=5.0×10−19 J. Find KEmax.
Example 24
easy
Express the work function ϕ=4.8×10−19 J in electronvolts. (1 eV=1.6×10−19 J)
Example 25
easy
A photon has wavelength λ=500 nm. Find its energy. (h=6.6×10−34, c=3×108)
Example 26
medium
The stopping voltage for ejected electrons is Vs=0.8 V. Find their maximum kinetic energy (e=1.6×10−19 C).
Example 27
medium
A metal emits electrons with KEmax=1.5×10−19 J under light of f=7×1014 Hz. Find ϕ. (h=6.6×10−34)
Example 28
medium
A metal has threshold wavelength λ0=500 nm. Find its work function. (h=6.6×10−34, c=3×108)
Example 29
medium
Find the threshold wavelength for a metal with ϕ=6.0×10−19 J. (h=6.6×10−34, c=3×108)
Example 30
medium
A photon ejects an electron with KEmax=4.0×10−19 J. Find the stopping voltage (e=1.6×10−19 C).
Example 31
medium
A graph of KEmax versus f has slope h and y-intercept −ϕ. If the slope is 6.6×10−34 J s and intercept is −3.3×10−19 J, find the threshold frequency.
Example 32
medium
Two metals have ϕA=2.0 eV and ϕB=4.0 eV. Identical photons of E=5.0 eV hit each. Which emits faster electrons?
Example 33
medium
A laser delivers 1×1018 photons per second of energy 4×10−19 J each. Find the laser's power.
Example 34
hard
A photon of λ=250 nm hits a metal with threshold wavelength λ0=350 nm. Find KEmax. (h=6.6×10−34, c=3×108)
Example 35
hard
A photon ejects an electron whose stopping voltage is 1.2 V. The metal's work function is 3.0×10−19 J. Find the photon frequency (h=6.6×10−34, e=1.6×10−19 C).
Example 36
hard
A metal of work function ϕ=2.8×10−19 J is illuminated with light of λ=400 nm. Will electrons be emitted? (h=6.6×10−34, c=3×108)
Example 37
hard
A photoelectric cell is illuminated by red light (f=4×1014 Hz) and ejected electrons have KEmax=1.0×10−19 J. The light is replaced with blue light of f=7×1014 Hz. Find the new KEmax. (h=6.6×10−34)
Example 38
challenge
Light of λ=200 nm shines on a metal with ϕ=3.0 eV. Find KEmax in eV. (h=6.6×10−34, c=3×108, 1 eV=1.6×10−19 J)