Magnetic Field Physics Example 2

Solution

1. 1
   Use the force formula for a current-carrying wire in a magnetic field: $F = BIL\sin\theta$, where $B$ is field strength, $I$ is current, $L$ is wire length, and $\theta$ is the angle between wire and field.
2. 2
   Identify given values: $B = 0.2\,\text{T}$, $I = 5\,\text{A}$, $L = 0.3\,\text{m}$. Since the wire is perpendicular to the field, $\theta = 90°$ and $\sin 90° = 1$.
3. 3
   Substitute and calculate: $$F = 0.2 \times 5 \times 0.3 \times 1 = 0.3\,\text{N}$$