Image Formation Examples in Physics

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Image Formation.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Physics.

Concept Recap

Image formation is the process by which reflected or refracted light creates an image that can be real or virtual, upright or inverted, and magnified or reduced.

Your eye or a screen sees an image based on where the outgoing rays meet or appear to meet.

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How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Image Formation starts by following rays or wavefronts through boundaries, materials, and image locations.

Common stuck point: Students often know a formula related to image formation but skip the recognition step: Am I tracking how light travels through space or materials, including boundary rules and image location when needed? That leads to a correct-looking substitution attached to the wrong physical model.

Sense of Study hint: Ask: Am I tracking how light travels through space or materials, including boundary rules and image location when needed?

Worked Examples

Example 1

medium
A converging lens with f=20 cmf = 20 \text{ cm} has an object at do=30 cmd_o = 30 \text{ cm}. Find did_i.

Answer

di=60 cmd_i = 60 \text{ cm}

First step

1
Thin lens: 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}.

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Example 2

medium
A concave mirror (f=15 cmf=15 \text{ cm}) has an object at do=10 cmd_o=10 \text{ cm}. Find did_i and mm.

Example 3

medium
Using f=10f=-10 cm and do=20d_o=20 cm (above), find mm and confirm the image type.

Example 4

hard
A converging lens with f=8 cmf = 8 \text{ cm} has an object 6 cm tall at do=24 cmd_o = 24 \text{ cm}. Describe the image fully.

Example 5

hard
A diverging lens forms a virtual image at di=12 cmd_i=-12 \text{ cm} when the object is at do=24 cmd_o=24 \text{ cm}. Find ff and mm.

Example 6

hard
A converging lens (f=10f=10 cm) forms an image with m=4|m|=4. Find both possible object distances.

Example 7

hard
Why does a virtual image lack the ability to be projected, even though we still call it an image?

Example 8

challenge
Two converging lenses (each f=10f=10 cm) are 30 cm apart. An object sits 20 cm in front of lens 1. Find where the final image forms relative to lens 2.

Example 9

challenge
A concave mirror with f=20f=20 cm forms an image with hi=5 cmh_i = -5 \text{ cm} when the object is 4 cm tall. Find dod_o and did_i.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
An image with magnification m=2m = -2 is described how in size and orientation?

Example 2

easy
Can a virtual image be projected onto a screen?

Example 3

easy
An object 6 cm tall forms an image 3 cm tall and upright. Find the magnification.

Example 4

easy
A real image is always oriented how relative to the object for a single lens or mirror?

Example 5

easy
A virtual image from a single converging lens or mirror is oriented how?

Example 6

easy
An object and its image have do=20 cmd_o = 20 \text{ cm} and di=10 cmd_i = 10 \text{ cm}. Find the magnification.

Example 7

easy
If m>1|m| > 1, is the image larger or smaller than the object?

Example 8

easy
Why are virtual images still considered genuine images even though they cannot be projected?

Example 9

medium
A lens forms an image with do=25 cmd_o = 25 \text{ cm} and di=50 cmd_i = -50 \text{ cm}. Find the magnification and describe the image.

Example 10

medium
A 10 cm object forms a 4 cm inverted image. The object distance is do=25 cmd_o = 25 \text{ cm}. Find the image distance.

Example 11

medium
A concave mirror (f=10 cmf=10 \text{ cm}) has an object at do=40 cmd_o=40 \text{ cm}. Describe the image fully (location, size, orientation, type).

Example 12

medium
An image is upright and the same size as the object. What is the magnification, and what optical element gives this for any object distance?

Example 13

medium
A lens gives do=30 cmd_o = 30 \text{ cm}, di=60 cmd_i = 60 \text{ cm}, object height 5 cm. Find the image height and orientation.

Example 14

medium
A real image forms at di=20 cmd_i = 20 \text{ cm} and is half the object's height. Find the object distance.

Example 15

challenge
A converging lens (f=12 cmf=12 \text{ cm}) has an object at do=18 cmd_o=18 \text{ cm}. Find the full image description including height for a 3 cm object.

Example 16

challenge
An object placed 10 cm from a lens gives an upright image 3 times as tall. Find the focal length.

Example 17

challenge
A concave mirror gives an image at di=30 cmd_i = -30 \text{ cm} (virtual) when the object is at do=12 cmd_o = 12 \text{ cm}. Find the focal length and magnification.

Example 18

medium
An object 8 cm tall forms an image 2 cm tall and inverted. Find the magnification.

Example 19

medium
A lens gives do=15 cmd_o=15 \text{ cm} and di=30 cmd_i=-30 \text{ cm}. Describe the image type and orientation.

Example 20

medium
An object forms a real image 3 times its height at di=60 cmd_i = 60 \text{ cm}. Find the object distance.

Example 21

easy
An object 4 cm tall produces a 6 cm tall inverted image. Find mm.

Example 22

easy
do=30 cmd_o = 30 \text{ cm} and di=15 cmd_i = 15 \text{ cm}. Find mm.

Example 23

easy
A 5 cm object has m=0.4m = -0.4. Find the image height.

Example 24

easy
do=40 cmd_o = 40 \text{ cm}, di=20 cmd_i = -20 \text{ cm}. Find mm and describe the image.

Example 25

medium
For the lens above (f=20f=20 cm, do=30d_o=30 cm, di=60d_i=60 cm), find mm.

Example 26

medium
An 8 cm object forms a 24 cm inverted image at di=90d_i = 90 cm. Find dod_o.

Example 27

medium
do=12 cmd_o = 12 \text{ cm}, di=24 cmd_i = 24 \text{ cm}, object height ho=4 cmh_o = 4 \text{ cm}. Find hih_i.

Example 28

medium
A real image is 1/31/3 the object's height and at di=20d_i = 20 cm. Find dod_o.

Example 29

medium
A diverging lens has f=10 cmf = -10 \text{ cm}. An object sits at do=20 cmd_o = 20 \text{ cm}. Find did_i.

Example 30

medium
A convex (diverging) mirror with f=20 cmf = -20 \text{ cm} shows an object at do=30 cmd_o = 30 \text{ cm}. Find did_i.

Example 31

medium
A lens forms a real image of the same height as the object at di=30 cmd_i = 30 \text{ cm}. Find dod_o and ff.

Example 32

hard
A concave mirror with f=10 cmf=10 \text{ cm} has an object at do=8 cmd_o=8 \text{ cm}. Find did_i and mm.

Example 33

hard
An upright image is twice the object's height. The object is at do=15 cmd_o = 15 \text{ cm}. Find did_i and the focal length (assuming a single lens or mirror).

Example 34

hard
An object is at do=2fd_o = 2f in front of a converging lens. Find did_i in terms of ff, and find mm.

Example 35

hard
A 2 cm coin is viewed through a magnifying glass (f=5f=5 cm) held 4 cm above. Find the apparent height of the image.

Related Concepts

Background Knowledge

These ideas may be useful before you work through the harder examples.

ray diagrammirrorslenses