Equilibrium Physics Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

medium
An object is in equilibrium under three forces: F1=10 NF_1 = 10 \text{ N} east, F2=10 NF_2 = 10 \text{ N} north. What is the magnitude and direction of the third force F3F_3?

Solution

  1. 1
    For equilibrium, F3F_3 must be equal and opposite to the resultant of F1F_1 and F2F_2.
  2. 2
    Resultant of F1F_1 and F2F_2: R=102+102=10214.1 NR = \sqrt{10^2 + 10^2} = 10\sqrt{2} \approx 14.1 \text{ N} at 45°45° north of east.
  3. 3
    F3=14.1 NF_3 = 14.1 \text{ N} directed 45°45° south of west.

Answer

F314.1 N at 45° south of westF_3 \approx 14.1 \text{ N at } 45° \text{ south of west}
Equilibrium requires that the vector sum of all forces is zero. The third force must exactly cancel the resultant of the other two.

About Equilibrium

A state in which all forces acting on an object balance so that the net force equals zero and there is no acceleration.

Learn more about Equilibrium →

More Equilibrium Examples