Electrical Power Physics Example 4

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Example 4

medium
A kettle is rated at 2000 W2000 \text{ W} and operates on a 250 V250 \text{ V} supply. (a) What current does it draw? (b) What is its resistance? (c) How much energy does it use in 3 minutes3 \text{ minutes}?

Solution

  1. 1
    (a) I=PV=2000250=8 AI = \frac{P}{V} = \frac{2000}{250} = 8 \text{ A}.
  2. 2
    (b) R=VI=2508=31.25 ΩR = \frac{V}{I} = \frac{250}{8} = 31.25 \text{ } \Omega. Or: R=V2P=25022000=31.25 ΩR = \frac{V^2}{P} = \frac{250^2}{2000} = 31.25 \text{ } \Omega.
  3. 3
    (c) E=Pt=2000×(3×60)=2000×180=360,000 J=360 kJE = Pt = 2000 \times (3 \times 60) = 2000 \times 180 = 360{,}000 \text{ J} = 360 \text{ kJ}.

Answer

(a)  8 A;(b)  31.25 Ω;(c)  360 kJ(a)\; 8 \text{ A}; \quad (b)\; 31.25 \text{ } \Omega; \quad (c)\; 360 \text{ kJ}
Power ratings on appliances tell you the energy consumption rate. Combining P=VIP = VI with Ohm's law gives useful formulas: P=I2RP = I^2R and P=V2/RP = V^2/R. Energy is power × time.

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The rate at which electrical energy is converted to other forms of energy (heat, light, motion). Measured in watts (W).

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