Electrical Power Physics Example 3

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Example 3

medium
An electric kettle rated at 2000 W2000 \text{ W} operates for 3 minutes3 \text{ minutes}. How much energy does it use in kJ?

Solution

  1. 1
    Convert time: 3 min=180 s3 \text{ min} = 180 \text{ s}.
  2. 2
    Energy: E=Pt=2000×180=360,000 J=360 kJE = Pt = 2000 \times 180 = 360{,}000 \text{ J} = 360 \text{ kJ}

Answer

E=360 kJE = 360 \text{ kJ}
Electrical energy consumption equals power times time. High-power appliances use significant energy even in short periods.

About Electrical Power

The rate at which electrical energy is converted to other forms of energy (heat, light, motion). Measured in watts (W).

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