Electric Potential Physics Example 2

Follow the full solution, then compare it with the other examples linked below.

Example 2

hard
How much work is needed to move a 3ร—10โˆ’6ย C3 \times 10^{-6} \text{ C} charge from a point at 200ย V200 \text{ V} to a point at 500ย V500 \text{ V}?

Solution

  1. 1
    Work equals charge times potential difference: W=qฮ”VW = q\Delta V.
  2. 2
    W=3ร—10โˆ’6ร—(500โˆ’200)=3ร—10โˆ’6ร—300W = 3 \times 10^{-6} \times (500 - 200) = 3 \times 10^{-6} \times 300
  3. 3
    W=9ร—10โˆ’4ย J=0.9ย mJW = 9 \times 10^{-4} \text{ J} = 0.9 \text{ mJ}

Answer

W=9ร—10โˆ’4ย JW = 9 \times 10^{-4} \text{ J}
The work done on a charge moving through a potential difference equals qฮ”Vq\Delta V. This is analogous to the work done by gravity when lifting an object through a height difference.

About Electric Potential

The electric potential energy per unit charge at a point in an electric field. Measured in volts (V).

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