Circular Motion Physics Example 2

Solution

1. 1
   Circumference of orbit: $C = 2\pi r = 2\pi \times 6.8 \times 10^6 = 4.27 \times 10^7 \text{ m}$.
2. 2
   Orbital speed: $$v = \frac{C}{T} = \frac{4.27 \times 10^7}{5400} \approx 7913 \text{ m/s}$$
3. 3
   Centripetal acceleration: $$a_c = \frac{v^2}{r} = \frac{7913^2}{6.8 \times 10^6} = \frac{6.26 \times 10^7}{6.8 \times 10^6} \approx 9.2 \text{ m/s}^2$$