Centripetal Force Physics Example 3

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Example 3

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A satellite orbits Earth at radius r=7ร—106ย mr = 7 \times 10^6 \text{ m} with speed v=7500ย m/sv = 7500 \text{ m/s}. What is the centripetal acceleration?

Solution

  1. 1
    Use the centripetal acceleration formula: ac=v2ra_c = \frac{v^2}{r}.
  2. 2
    ac=750027ร—106=5.625ร—1077ร—106โ‰ˆ8.04ย m/s2a_c = \frac{7500^2}{7 \times 10^6} = \frac{5.625 \times 10^7}{7 \times 10^6} \approx 8.04 \text{ m/s}^2

Answer

acโ‰ˆ8.04ย m/s2a_c \approx 8.04 \text{ m/s}^2
A satellite in orbit is in continuous free-fall, with gravity providing the centripetal force. The centripetal acceleration is slightly less than gg at the surface because the satellite is farther from Earth's center.

About Centripetal Force

The net inward force required to keep an object moving along a circular path, directed toward the centre of the circle, equal to mv2/rmv^2/r where.

Learn more about Centripetal Force โ†’

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