Centripetal Force Physics Example 1

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Example 1

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A 0.5 kg0.5 \text{ kg} ball on a 1.2 m1.2 \text{ m} string is swung in a horizontal circle at 4 m/s4 \text{ m/s}. What is the centripetal force?

Solution

  1. 1
    Recall the centripetal force formula: Fc=mv2rF_c = \frac{mv^2}{r}, where mm is mass, vv is speed, and rr is radius.
  2. 2
    Identify the given values: m=0.5 kgm = 0.5 \text{ kg}, v=4 m/sv = 4 \text{ m/s}, r=1.2 mr = 1.2 \text{ m}.
  3. 3
    Substitute and calculate: Fc=0.5×421.2=0.5×161.2=81.26.67 NF_c = \frac{0.5 \times 4^2}{1.2} = \frac{0.5 \times 16}{1.2} = \frac{8}{1.2} \approx 6.67 \text{ N}

Answer

Fc6.67 NF_c \approx 6.67 \text{ N}
Centripetal force is the net force directed toward the center of the circular path. It is provided by the string tension in this case and keeps the ball moving in a circle.

About Centripetal Force

The net inward force required to keep an object moving along a circular path, directed toward the centre of the circle, equal to mv2/rmv^2/r where.

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