Volumes of Revolution Math Example 1

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Example 1

easy
Find the volume of the solid formed by rotating f(x)=xf(x) = \sqrt{x} around the xx-axis from x=0x=0 to x=4x=4.

Solution

  1. 1
    Use the disc method for revolution about the xx-axis: V=ฯ€โˆซab[f(x)]2โ€‰dxV = \pi\int_a^b [f(x)]^2\,dx. Since f(x)=xf(x) = \sqrt{x}, [f(x)]2=x[f(x)]^2 = x.
  2. 2
    Set up the integral: V=ฯ€โˆซ04xโ€‰dxV = \pi\int_0^4 x\,dx
  3. 3
    Evaluate: V=ฯ€[x22]04=ฯ€โ‹…162=8ฯ€V = \pi\left[\frac{x^2}{2}\right]_0^4 = \pi\cdot\frac{16}{2} = 8\pi

Answer

V=8ฯ€V = 8\pi
The disc method stacks thin circular discs. Each has radius f(x)f(x) and thickness dxdx, giving volume element ฯ€[f(x)]2โ€‰dx\pi[f(x)]^2\,dx.

About Volumes of Revolution

Finding the volume of a three-dimensional solid formed by rotating a two-dimensional region around an axis. The disc/washer method uses circular cross-sections perpendicular to the axis; the shell method uses cylindrical shells parallel to the axis.

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