u-Substitution Examples: 49 Problems with Answers

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of u-Substitution.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

An integration technique where you substitute u=g(x) and du=g′(x) dx to transform a complicated integral into a simpler one. It is the reverse of the chain rule for differentiation.

When you see a composite function inside an integral along with its inner derivative lurking nearby, substitution collapses the composition into a single variable. It's like un-nesting a function: replace the inner part with u, and the integral becomes simpler.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: u-Substitution sets u=g(x) so du=g′(x) dx, collapsing a composite-times-inner-derivative integral into a simple one in u.

Common stuck point: The procedure for u-substitution is the easy part; the trap is forgetting to convert dx via du=g′(x) dx. Asking "Is there an inner function g(x) inside, with its derivative g′(x) also present as a factor?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Is there an inner function g(x) inside, with its derivative g′(x) also present as a factor?

Worked Examples

Example 1

easy
Find ∫3x2(x3+1)4 dx.

Answer

(x3+1)55+C

First step

1
Let u=x3+1, so du=3x2 dx.

Full solution

  1. 2
    Integral becomes ∫u4 du=u55+C.
  2. 3
    Substitute back: (x3+1)55+C.
3x2 dx is exactly du, so the substitution is perfect. After substitution the integral reduces to a simple power rule.

Example 2

medium
Evaluate ∫01xex2 dx.

Example 3

medium
Evaluate ∫x2x3+1 dx.

Example 4

medium
Evaluate ∫x x2+53 dx.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Find ∫cos⁡(5x) dx.

Example 2

hard
Find ∫ln⁡xx dx.

Example 3

easy
Evaluate ∫2x(x2+1)3 dx using u=x2+1.

Example 4

easy
Evaluate ∫cos⁡(3x) dx.

Example 5

easy
Evaluate ∫e5x dx.

Example 6

easy
Evaluate ∫12x+1 dx.

Example 7

easy
Evaluate ∫(3x+2)5 dx.

Example 8

easy
Evaluate ∫2x ex2 dx.

Example 9

easy
Evaluate ∫sin⁡x cos⁡x dx using u=sin⁡x.

Example 10

easy
For the definite integral ∫032x(x2) dx with u=x2, what are the new limits?

Example 11

medium
Evaluate ∫xx2+4 dx.

Example 12

medium
Evaluate the definite integral ∫02x(x2+1)3 dx.

Example 13

medium
Evaluate ∫ln⁡xx dx.

Example 14

medium
Evaluate ∫xx2+1 dx.

Example 15

medium
Evaluate ∫sec⁡2x tan⁡3x dx.

Example 16

medium
Evaluate ∫x2(x3+2)4 dx.

Example 17

challenge
Evaluate ∫0π/2sin⁡2x cos⁡x dx.

Example 18

challenge
Evaluate ∫xx+1 dx (note: the inner derivative is not present).

Example 19

challenge
Evaluate ∫1x (1+x) dx.

Example 20

medium
Evaluate ∫6x(3x2+1)2 dx.

Example 21

medium
Evaluate ∫tan⁡x dx (write tan⁡x=sin⁡xcos⁡x).

Example 22

medium
Evaluate ∫012xx2+1 dx.

Example 23

easy
Evaluate ∫4x3(x4+1)2 dx.

Example 24

easy
Evaluate ∫sin⁡(7x) dx.

Example 25

easy
Evaluate ∫e−2x dx.

Example 26

easy
Evaluate ∫13x−5 dx.

Example 27

easy
Evaluate ∫(5x+3)4 dx.

Example 28

medium
Evaluate ∫cos⁡x sin⁡4x dx.

Example 29

medium
Evaluate ∫2xx2+4 dx.

Example 30

medium
Evaluate ∫01x(x2+1)4 dx.

Example 31

medium
Evaluate ∫sec⁡2(3x) dx.

Example 32

medium
Evaluate ∫exex+2 dx.

Example 33

medium
Evaluate ∫cos⁡3x dx by writing cos⁡3x=(1−sin⁡2x)cos⁡x and substituting u=sin⁡x.

Example 34

medium
Evaluate ∫0π/4tan⁡xsec⁡2x dx.

Example 35

medium
Evaluate ∫(ln⁡x)3x dx.

Example 36

medium
Evaluate ∫esin⁡xcos⁡x dx.

Example 37

hard
Evaluate ∫02x4−x2 dx.

Example 38

hard
Evaluate ∫x1+x2 dx.

Example 39

hard
Evaluate ∫x3x2+1 dx via u=x2+1.

Example 40

hard
Evaluate ∫x2(x3+2)4 dx.

Example 41

hard
Evaluate ∫sin⁡x1+cos⁡x dx.

Example 42

hard
Evaluate ∫0ln⁡2ex1+ex dx.

Example 43

hard
Evaluate ∫1x ln⁡x dx.

Example 44

challenge
Evaluate ∫sin⁡5x dx by writing sin⁡5x=(1−cos⁡2x)2sin⁡x and substituting u=cos⁡x.

Example 45

challenge
Evaluate ∫11+x dx.

Background Knowledge

These ideas may be useful before you work through the harder examples.

integralchain rule