Trigonometric Functions Math Example 4

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Example 4

hard
If sinθ=35\sin\theta = \frac{3}{5} and θ\theta is in Quadrant II, find cosθ\cos\theta and tanθ\tan\theta.

Solution

  1. 1
    Use sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1: cos2θ=1925=1625\cos^2\theta = 1 - \frac{9}{25} = \frac{16}{25}, so cosθ=±45\cos\theta = \pm\frac{4}{5}.
  2. 2
    In Quadrant II, cosine is negative: cosθ=45\cos\theta = -\frac{4}{5}.
  3. 3
    tanθ=sinθcosθ=3/54/5=34\tan\theta = \frac{\sin\theta}{\cos\theta} = \frac{3/5}{-4/5} = -\frac{3}{4}.

Answer

cosθ=45,tanθ=34\cos\theta = -\frac{4}{5}, \quad \tan\theta = -\frac{3}{4}
The Pythagorean identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 lets you find one trig function from another. The quadrant determines the sign.

About Trigonometric Functions

Trigonometric functions (sin, cos, tan, etc.) relate angles in right triangles to side ratios and extend to periodic functions of real numbers via the unit circle.

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