Pythagorean Trigonometric Identities Math Example 4

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Example 4

hard
Simplify sec2(θ)1csc2(θ)1\frac{\sec^2(\theta) - 1}{\csc^2(\theta) - 1}.

Solution

  1. 1
    Use the Pythagorean identities: sec2θ1=tan2θ\sec^2\theta - 1 = \tan^2\theta and csc2θ1=cot2θ\csc^2\theta - 1 = \cot^2\theta.
  2. 2
    So the expression becomes tan2θcot2θ=tan2θtan2θ=tan4θ\frac{\tan^2\theta}{\cot^2\theta} = \tan^2\theta \cdot \tan^2\theta = \tan^4\theta.

Answer

tan4(θ)\tan^4(\theta)
Using the Pythagorean identities sec2θ=1+tan2θ\sec^2\theta = 1 + \tan^2\theta and csc2θ=1+cot2θ\csc^2\theta = 1 + \cot^2\theta, we can replace the numerator and denominator. Since cotθ=1tanθ\cot\theta = \frac{1}{\tan\theta}, dividing by cot2θ\cot^2\theta is the same as multiplying by tan2θ\tan^2\theta.

About Pythagorean Trigonometric Identities

The fundamental identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 and its derived forms: 1+tan2θ=sec2θ1 + \tan^2\theta = \sec^2\theta and 1+cot2θ=csc2θ1 + \cot^2\theta = \csc^2\theta.

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