Standard Deviation Math Example 1

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Example 1

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Find the population standard deviation of {2,4,4,4,5,5,7,9}\{2, 4, 4, 4, 5, 5, 7, 9\}.

Solution

  1. 1
    Compute the mean: xห‰=2+4+4+4+5+5+7+98=408=5\bar{x} = \frac{2+4+4+4+5+5+7+9}{8} = \frac{40}{8} = 5.
  2. 2
    Find each squared deviation: (2โˆ’5)2=9(2-5)^2 = 9, (4โˆ’5)2=1(4-5)^2 = 1 (three times), (5โˆ’5)2=0(5-5)^2 = 0 (twice), (7โˆ’5)2=4(7-5)^2 = 4, (9โˆ’5)2=16(9-5)^2 = 16.
  3. 3
    Sum of squared deviations: 9+1+1+1+0+0+4+16=329 + 1 + 1 + 1 + 0 + 0 + 4 + 16 = 32.
  4. 4
    Variance: ฯƒ2=328=4\sigma^2 = \frac{32}{8} = 4.
  5. 5
    Standard deviation: ฯƒ=4=2\sigma = \sqrt{4} = 2.

Answer

ฯƒ=2\sigma = 2
The standard deviation measures how spread out data values are from the mean. A small standard deviation means values cluster near the mean, while a large one indicates greater spread.

About Standard Deviation

The standard deviation measures the average distance of data values from the mean, giving a typical spread around the center.

Learn more about Standard Deviation โ†’

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