Series Math Example 3

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Example 3

easy
Write the first four partial sums of 1โˆ’12+13โˆ’14+โ‹ฏ1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \cdots

Solution

  1. 1
    S1=1S_1 = 1.
  2. 2
    S2=12S_2 = \frac{1}{2}.
  3. 3
    S3=56S_3 = \frac{5}{6}.
  4. 4
    S4=712S_4 = \frac{7}{12}.

Answer

S1=1,โ€…โ€ŠS2=12,โ€…โ€ŠS3=56,โ€…โ€ŠS4=712S_1=1,\; S_2=\frac{1}{2},\; S_3=\frac{5}{6},\; S_4=\frac{7}{12}
This alternating harmonic series converges to lnโก2โ‰ˆ0.693\ln 2 \approx 0.693. Partial sums alternate above and below the limit, closing in from both sides.

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The result of adding all the terms of a sequence together, either finitely or infinitely many terms.

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