Quadratic Standard Form Math Example 2

Follow the full solution, then compare it with the other examples linked below.

Example 2

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Convert y=โˆ’(xโˆ’2)2+5y = -(x-2)^2 + 5 to standard form.

Solution

  1. 1
    Expand (xโˆ’2)2=x2โˆ’4x+4(x-2)^2 = x^2 - 4x + 4.
  2. 2
    Apply the negative: โˆ’(x2โˆ’4x+4)+5=โˆ’x2+4xโˆ’4+5-(x^2 - 4x + 4) + 5 = -x^2 + 4x - 4 + 5.
  3. 3
    Simplify: y=โˆ’x2+4x+1y = -x^2 + 4x + 1.

Answer

y=โˆ’x2+4x+1y = -x^2 + 4x + 1
To convert from vertex form to standard form, expand the squared binomial, distribute the leading coefficient, and combine like terms.

About Quadratic Standard Form

The standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0, where aโ‰ 0a \neq 0 and aa, bb, cc are real number coefficients.

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