Example 1 — Compare two classes fairly
EasyProblem
Class A: 12 of 20 passed. Class B: 21 of 35 passed. Which class had the higher pass proportion?
Solution
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The classes are different sizes, so compare shares with .
Name the structure before touching arithmetic — that is what makes the right method obvious.
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Ask the recognition question: Am I expressing a count as a fraction of its own total so different-sized groups compare fairly?
If the answer is yes, the concept applies; the cue, not a keyword, decides the method.
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Divide each count by its own total to get a proportion.
The rule is chosen only after the structure matches, so the steps mean something.
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A: ; B: .
Keep units, shape, or answer form tied to the story so the work does not become symbol pushing.
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Check the answer against the original question.
It should fit the mental model — share of the whole, not raw count. If it does not, revisit the recognition step before changing the arithmetic.
Answer
They tied — both passed
Takeaway: Equal proportions can hide unequal counts; the share is the fair comparison.