Polar Graphs Math Example 2

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Example 2

medium
Identify the type of polar curve r=2+2cosθr = 2 + 2\cos\theta and find key features.

Solution

  1. 1
    This has the form r=a+bcosθr = a + b\cos\theta with a=b=2a = b = 2. When a=ba = b, the curve is a cardioid.
  2. 2
    Maximum rr: when cosθ=1\cos\theta = 1 (θ=0\theta = 0), r=4r = 4. Minimum rr: when cosθ=1\cos\theta = -1 (θ=π\theta = \pi), r=0r = 0.
  3. 3
    The curve passes through the origin when θ=π\theta = \pi and has its farthest point at (4,0)(4, 0).
  4. 4
    The graph is symmetric about the polar axis (the xx-axis) because replacing θ\theta with θ-\theta gives the same equation.

Answer

Cardioid with maximum r=4 at θ=0\text{Cardioid with maximum } r = 4 \text{ at } \theta = 0
A cardioid (meaning 'heart-shaped') occurs when a=ba = b in r=a+bcosθr = a + b\cos\theta or r=a+bsinθr = a + b\sin\theta. The curve touches the origin once, creating its characteristic cusp. Symmetry depends on whether cosine (x-axis symmetry) or sine (y-axis symmetry) is used.

About Polar Graphs

Graphs of equations in the form r=f(θ)r = f(\theta), producing curves such as rose curves, cardioids, limaçons, and circles in the polar plane.

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