Periodic Functions Math Example 2

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Example 2

medium
Find the period of g(x)=cosโก(3x)g(x) = \cos(3x) and sketch one complete cycle.

Solution

  1. 1
    The standard cosine cosโก(x)\cos(x) has period 2ฯ€2\pi. When the argument is 3x3x, the period is compressed by a factor of 33.
  2. 2
    Set 3x=2ฯ€3x = 2\pi to find when one full cycle completes: x=2ฯ€3x = \frac{2\pi}{3}.
  3. 3
    One complete cycle of g(x)=cosโก(3x)g(x) = \cos(3x) occurs on the interval [0,2ฯ€3]\left[0, \frac{2\pi}{3}\right]. The function starts at g(0)=1g(0)=1, reaches โˆ’1-1 at x=ฯ€3x=\frac{\pi}{3}, and returns to 11 at x=2ฯ€3x=\frac{2\pi}{3}.

Answer

Period =2ฯ€3= \dfrac{2\pi}{3}
Replacing xx with bxbx scales the period from 2ฯ€2\pi to 2ฯ€/b2\pi/b. For b=3b=3, the period is 2ฯ€/3โ‰ˆ2.092\pi/3 \approx 2.09, meaning the cosine wave completes three full oscillations over the interval [0,2ฯ€][0, 2\pi].

About Periodic Functions

A function that repeats its values at regular intervals: f(x+T)=f(x)f(x + T) = f(x) for all xx, where TT is the smallest positive period.

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