Parametric Equations Math Example 2

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Example 2

medium
Eliminate the parameter from x=3cosโก(t)x = 3\cos(t) and y=3sinโก(t)y = 3\sin(t).

Solution

  1. 1
    From the parametric equations: cosโก(t)=x3\cos(t) = \frac{x}{3} and sinโก(t)=y3\sin(t) = \frac{y}{3}.
  2. 2
    Use the Pythagorean identity cosโก2(t)+sinโก2(t)=1\cos^2(t) + \sin^2(t) = 1.
  3. 3
    Substitute: (x3)2+(y3)2=1\left(\frac{x}{3}\right)^2 + \left(\frac{y}{3}\right)^2 = 1, which gives x29+y29=1\frac{x^2}{9} + \frac{y^2}{9} = 1.
  4. 4
    Simplify: x2+y2=9x^2 + y^2 = 9.

Answer

x2+y2=9x^2 + y^2 = 9
When parametric equations involve sine and cosine, the Pythagorean identity is the key to eliminating the parameter. The result is a circle of radius 3 centered at the origin. The parameter tt represents the angle, tracing the circle counterclockwise as tt increases.

About Parametric Equations

A way of defining a curve by expressing both xx and yy as separate functions of a third variable (parameter), typically tt: x=f(t)x = f(t), y=g(t)y = g(t).

Learn more about Parametric Equations โ†’

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