Multiple Representations Math Example 4

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Example 4

hard
A graph passes through (โˆ’2,0)(-2,0), (0,โˆ’4)(0,-4), and (1,0)(1,0) and appears to be a parabola. Find the quadratic equation and verify using all three points.

Solution

  1. 1
    The xx-intercepts โˆ’2-2 and 11 give factors (x+2)(xโˆ’1)(x+2)(x-1), so f(x)=a(x+2)(xโˆ’1)f(x) = a(x+2)(x-1).
  2. 2
    Use yy-intercept (0,โˆ’4)(0,-4): f(0)=a(2)(โˆ’1)=โˆ’2a=โˆ’4โ‡’a=2f(0)=a(2)(-1)=-2a=-4 \Rightarrow a=2. So f(x)=2(x+2)(xโˆ’1)=2x2+2xโˆ’4f(x)=2(x+2)(x-1)=2x^2+2x-4.
  3. 3
    Verify: f(โˆ’2)=2(0)(โˆ’3)=0f(-2)=2(0)(-3)=0 โœ“; f(0)=2(2)(โˆ’1)=โˆ’4f(0)=2(2)(-1)=-4 โœ“; f(1)=2(3)(0)=0f(1)=2(3)(0)=0 โœ“.

Answer

f(x)=2x2+2xโˆ’4f(x) = 2x^2 + 2x - 4
Graph information (intercepts) provides constraints to determine the algebraic formula. Using the factored form from xx-intercepts and the yy-intercept to find the leading coefficient is an efficient strategy.

About Multiple Representations

Every function can be expressed in four equivalent ways: as an algebraic formula, a table of input-output pairs, a graph on the coordinate plane, or a verbal description. Each representation highlights different properties and is useful in different contexts.

Learn more about Multiple Representations โ†’

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