Multi-Step Equations Examples: 46 Problems with Answers

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Multi-Step Equations.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Solving equations that require more than one inverse operation—typically involving distributing, combining like terms, and moving variables to one side before isolating the variable.

A one-step equation is like unwrapping one layer of packaging. A multi-step equation has several layers: first simplify each side (distribute, combine like terms), then peel off operations one at a time until x stands alone. Think of it as cleaning up a messy room before finding what you're looking for.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Distribute and combine like terms first, then undo operations one at a time until the variable is alone.

Common stuck point: The procedure for multi-step equations is the easy part; the trap is distributing only to the first term. Asking "Does isolating x take more than one step — distributing, combining, or moving variables first?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Does isolating x take more than one step — distributing, combining, or moving variables first?

Worked Examples

Example 1

easy
Solve 3(x+2)−4=14.

Answer

x=4

First step

1
Distribute: 3x+6−4=14.

Full solution

  1. 2
    Simplify: 3x+2=14.
  2. 3
    Subtract 2: 3x=12.
  3. 4
    Divide by 3: x=4.
Multi-step equations require multiple inverse operations. Distribute first, then combine like terms, then isolate the variable.

Example 2

medium
Solve x+12−x−34=3.

Example 3

medium
Solve 4(x−3)+2x=18.

Example 4

medium
Solve 2x+13=x−22.

Example 5

medium
Identify whether 3(x+2)=3x+6 has one, no, or infinitely many solutions.

Example 6

hard
Solve 3(2x−1)−4(x+2)=5(x−3)+6.

Example 7

hard
A rectangle has perimeter 44 cm. Its length is 4 more than twice its width. Find the dimensions.

Example 8

challenge
A father is three times his son's age. In 10 years, the father will be twice the son's age. Find their current ages.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Solve 2(x−5)=8.

Example 2

hard
Solve 5−2(3x+1)=4x−7.

Example 3

easy
Solve 2x+3=11.

Example 4

easy
Solve 5x−7=18.

Example 5

easy
Solve 3(x+2)=15.

Example 6

easy
Solve x4+1=5.

Example 7

easy
Solve 2x+5=x+9.

Example 8

easy
Solve 4x−2=2x+6.

Example 9

easy
Solve 7=3x−5.

Example 10

easy
Solve 2x3=8.

Example 11

medium
Solve 3(2x−1)=4x+7.

Example 12

medium
Solve 5x−2(x−3)=18.

Example 13

medium
Solve x+12+x3=4.

Example 14

medium
Solve 2(x+4)=3(x−1).

Example 15

medium
Solve 6x+2=2(3x+1).

Example 16

medium
Solve 4(x−2)=4x+1.

Example 17

medium
Solve 3x−12=x+4.

Example 18

medium
Solve 3x+2(x−1)=13.

Example 19

medium
Solve x2+x3=5.

Example 20

challenge
Solve for x: ax+b=c (with a≠0), in terms of a, b, c.

Example 21

challenge
A number doubled, plus 7, equals three times the number minus 2. Find the number.

Example 22

challenge
Solve x2−x−34=x+12.

Example 23

easy
Solve 3x−4=11.

Example 24

easy
Solve x5−2=3.

Example 25

easy
Solve 5−x=2.

Example 26

easy
Solve x−13=4.

Example 27

easy
Solve −2x+7=1.

Example 28

medium
Solve 3x+5=2(x+7).

Example 29

medium
Solve x3+x6=5.

Example 30

medium
Solve 5(x−2)−3(x+1)=7.

Example 31

medium
Solve 3x+2−5x=8−x.

Example 32

medium
Solve 2(3x−1)+4=5x+7.

Example 33

medium
Solve 3x4−12=x2+1.

Example 34

medium
Solve 4(x+1)−2=3(x−2)+5.

Example 35

hard
Solve x+34−x−13=16.

Example 36

hard
Solve 2x−15=x+43.

Example 37

hard
Two consecutive integers add to −15. Set up and solve.

Example 38

hard
Solve for x in terms of a and b: a(x−b)=bx+a.

Background Knowledge

These ideas may be useful before you work through the harder examples.

solving linear equationsdistributive propertyexpressions