Midpoint Formula Math Example 1

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Example 1

easy
Find the midpoint of the segment joining (2,8)(2, 8) and (6,4)(6, 4).

Solution

  1. 1
    The midpoint of a segment is the average of the two endpoints' coordinates: M=(x1+x22,โ€‰y1+y22)M = \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}\right). Averaging 'splits the difference' equally.
  2. 2
    Identify the endpoints: (x1,y1)=(2,8)(x_1, y_1) = (2, 8) and (x2,y2)=(6,4)(x_2, y_2) = (6, 4). Compute the averages separately for xx and yy.
  3. 3
    Substitute: M=(2+62,โ€‰8+42)=(82,โ€‰122)=(4,6)M = \left(\frac{2+6}{2},\, \frac{8+4}{2}\right) = \left(\frac{8}{2},\, \frac{12}{2}\right) = (4, 6). Verify: the point (4,6)(4,6) lies exactly halfway between (2,8)(2,8) and (6,4)(6,4) โ€” the distance from (2,8)(2,8) to (4,6)(4,6) equals the distance from (4,6)(4,6) to (6,4)(6,4) (both equal 8\sqrt{8}).

Answer

M=(4,6)M = (4, 6)
The midpoint is simply the average of the xx-coordinates and the average of the yy-coordinates. It represents the exact centre of the line segment.

About Midpoint Formula

A formula for finding the point exactly halfway between two points in the coordinate plane, by averaging their coordinates.

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