L'Hopital's Rule Math Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

easy
Find lim⁑xβ†’1x2βˆ’1xβˆ’1\displaystyle\lim_{x \to 1} \frac{x^2 - 1}{x - 1} using L'HΓ΄pital's rule.

Solution

  1. 1
    1βˆ’11βˆ’1=00\frac{1-1}{1-1} = \frac{0}{0}, so apply L'HΓ΄pital.
  2. 2
    lim⁑xβ†’12x1=2\lim_{x\to1}\frac{2x}{1} = 2.

Answer

22
L'HΓ΄pital applies since the form is 0/00/0. Differentiate numerator and denominator separately. (Factoring would also work: (xβˆ’1)(x+1)xβˆ’1β†’x+1β†’2\frac{(x-1)(x+1)}{x-1} \to x+1 \to 2.)

About L'Hopital's Rule

If lim⁑xβ†’af(x)g(x)\lim_{x \to a} \frac{f(x)}{g(x)} is an indeterminate form 00\frac{0}{0} or ∞∞\frac{\infty}{\infty}, then lim⁑xβ†’af(x)g(x)=lim⁑xβ†’afβ€²(x)gβ€²(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)} provided the right-hand limit exists (or is ±∞\pm\infty).

Learn more about L'Hopital's Rule β†’

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