L'Hopital's Rule Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
Find lim⁑xβ†’0sin⁑xx\displaystyle\lim_{x \to 0} \frac{\sin x}{x} using L'HΓ΄pital's rule.

Solution

  1. 1
    Direct substitution: sin⁑00=00\frac{\sin 0}{0} = \frac{0}{0} β€” indeterminate form.
  2. 2
    Apply L'HΓ΄pital: differentiate numerator and denominator separately.
  3. 3
    lim⁑xβ†’0sin⁑xx=lim⁑xβ†’0cos⁑x1=cos⁑01=1\lim_{x\to 0}\frac{\sin x}{x} = \lim_{x\to 0}\frac{\cos x}{1} = \frac{\cos 0}{1} = 1.

Answer

11
L'HΓ΄pital's rule applies when we have a 00\frac{0}{0} form. Differentiate top and bottom independently (not using the quotient rule), then evaluate the limit.

About L'Hopital's Rule

If lim⁑xβ†’af(x)g(x)\lim_{x \to a} \frac{f(x)}{g(x)} is an indeterminate form 00\frac{0}{0} or ∞∞\frac{\infty}{\infty}, then lim⁑xβ†’af(x)g(x)=lim⁑xβ†’afβ€²(x)gβ€²(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)} provided the right-hand limit exists (or is ±∞\pm\infty).

Learn more about L'Hopital's Rule β†’

More L'Hopital's Rule Examples