Geometric Proofs Math Example 4

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Example 4

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Given that โ–ณABCโ‰…โ–ณDEF\triangle ABC \cong \triangle DEF, prove that the perimeters are equal.

Solution

  1. 1
    From congruence โ–ณABCโ‰…โ–ณDEF\triangle ABC \cong \triangle DEF: corresponding sides are equal, so AB=DEAB = DE, BC=EFBC = EF, CA=FDCA = FD.
  2. 2
    Perimeter of โ–ณABC=AB+BC+CA\triangle ABC = AB + BC + CA; perimeter of โ–ณDEF=DE+EF+FD\triangle DEF = DE + EF + FD.
  3. 3
    Substituting the equal pairs: perimeter of โ–ณDEF=AB+BC+CA\triangle DEF = AB + BC + CA = perimeter of โ–ณABC\triangle ABC.

Answer

The perimeters are equal.
Congruent triangles have all corresponding parts equal (CPCTC). Since the perimeter is the sum of the three sides, substituting the equal corresponding sides shows the perimeters must be equal.

About Geometric Proofs

Geometric proofs establish that a geometric claim is true by chaining justified statements from definitions, theorems, and givens.

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