Practice Factoring by Grouping in Math

Use these practice problems to test your method after reviewing the concept explanation and worked examples.

Quick Recap

A factoring technique for polynomials with four or more terms: group terms into pairs, factor the GCF from each pair, then factor out the common binomial factor.

Imagine four terms that seem unrelated. By cleverly grouping them into two pairs and factoring each pair separately, a common binomial factor often emergesβ€”like finding a hidden pattern by rearranging puzzle pieces.

Showing a random 20 of 50 problems.

Example 1

hard
Factor 8x3+12x2+10x+158x^3 + 12x^2 + 10x + 15 by grouping.

Example 2

challenge
Factor x3+x2yβˆ’xy2βˆ’y3x^3 + x^2y - xy^2 - y^3 by grouping.

Example 3

easy
Factor xy+3x+2y+6xy + 3x + 2y + 6.

Example 4

easy
Factor x3+x2+x+1x^3 + x^2 + x + 1 by grouping.

Example 5

easy
Factor 3x3+12x2+2x+83x^3 + 12x^2 + 2x + 8 by grouping.

Example 6

easy
Factor ab+4a+2b+8ab + 4a + 2b + 8 by grouping.

Example 7

medium
After factoring x3+3x2+2x+6x^3 + 3x^2 + 2x + 6 as x2(x+3)+2(x+3)x^2(x+3) + 2(x+3), what is the next step?

Example 8

easy
Complete the factoring: ax+ay+bx+by=(a+b)(___)ax + ay + bx + by = (a + b)(\_\_\_).

Example 9

medium
Factor 6x3βˆ’9x2βˆ’4x+66x^3 - 9x^2 - 4x + 6 by grouping.

Example 10

challenge
Factor x3+5x2βˆ’2xβˆ’10x^3 + 5x^2 - 2x - 10 and identify all real roots.

Example 11

easy
Factor 2x3+6x2+x+32x^3 + 6x^2 + x + 3 by grouping.

Example 12

challenge
Show that x3+3x2βˆ’xβˆ’3x^3 + 3x^2 - x - 3 factors by grouping, and find all real roots.

Example 13

medium
Factor x3βˆ’7x2βˆ’4x+28x^3 - 7x^2 - 4x + 28 by grouping.

Example 14

hard
Factor 4x3βˆ’12x2+9xβˆ’274x^3 - 12x^2 + 9x - 27 by grouping.

Example 15

medium
Factor 2axβˆ’4ay+3bxβˆ’6by2ax - 4ay + 3bx - 6by by grouping.

Example 16

hard
Factor 6x3+9x2βˆ’4xβˆ’66x^3 + 9x^2 - 4x - 6 by grouping.

Example 17

hard
Factor x3+5x2βˆ’xβˆ’5x^3 + 5x^2 - x - 5 completely.

Example 18

medium
Factor 3y3+6y2+4y+83y^3 + 6y^2 + 4y + 8 by grouping.

Example 19

hard
Factor x3βˆ’3x2+xβˆ’3x^3 - 3x^2 + x - 3 by grouping.

Example 20

medium
Factor 4x3+8x2βˆ’3xβˆ’64x^3 + 8x^2 - 3x - 6 by grouping.