Exponential Growth Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
A population of bacteria doubles every 33 hours. If there are initially 500500 bacteria, how many will there be after 1212 hours?

Solution

  1. 1
    The exponential growth model is P(t)=P0β‹…2t/dP(t) = P_0 \cdot 2^{t/d}, where dd is the doubling time.
  2. 2
    Substitute: P(12)=500β‹…212/3=500β‹…24P(12) = 500 \cdot 2^{12/3} = 500 \cdot 2^4.
  3. 3
    P(12)=500β‹…16=8,000P(12) = 500 \cdot 16 = 8{,}000.

Answer

8,000Β bacteria8{,}000 \text{ bacteria}
Exponential growth occurs when a quantity increases by a constant percentage over equal time intervals. The doubling-time formula P(t)=P0β‹…2t/dP(t) = P_0 \cdot 2^{t/d} is a special case of P(t)=P0β‹…btP(t) = P_0 \cdot b^t. In 12 hours, the population doubles 4 times: 500β†’1000β†’2000β†’4000β†’8000500 \to 1000 \to 2000 \to 4000 \to 8000.

About Exponential Growth

Exponential growth occurs when a quantity increases by a constant multiplicative factor over equal intervals.

Learn more about Exponential Growth β†’

More Exponential Growth Examples