Even and Odd Functions Math Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

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Is h(x)=x3+x2h(x) = x^3 + x^2 even, odd, or neither?

Solution

  1. 1
    h(βˆ’x)=(βˆ’x)3+(βˆ’x)2=βˆ’x3+x2h(-x) = (-x)^3 + (-x)^2 = -x^3 + x^2. Compare: h(x)=x3+x2h(x) = x^3 + x^2 and βˆ’h(x)=βˆ’x3βˆ’x2-h(x) = -x^3 - x^2.
  2. 2
    h(βˆ’x)β‰ h(x)h(-x) \neq h(x) and h(βˆ’x)β‰ βˆ’h(x)h(-x) \neq -h(x), so hh is neither even nor odd.

Answer

NeitherΒ evenΒ norΒ odd\text{Neither even nor odd}
A function that mixes even and odd powers of xx is typically neither even nor odd. Any function can be decomposed into even and odd parts: f(x)=f(x)+f(βˆ’x)2+f(x)βˆ’f(βˆ’x)2f(x) = \frac{f(x)+f(-x)}{2} + \frac{f(x)-f(-x)}{2}. Here the even part is x2x^2 and the odd part is x3x^3.

About Even and Odd Functions

An even function satisfies f(βˆ’x)=f(x)f(-x) = f(x) (symmetric about yy-axis); an odd function satisfies f(βˆ’x)=βˆ’f(x)f(-x) = -f(x) (rotational symmetry about origin).

Learn more about Even and Odd Functions β†’

More Even and Odd Functions Examples