Equivalence Classes Math Example 4

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Example 4

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Define fโˆผgf \sim g on functions from R\mathbb{R} to R\mathbb{R} by fโˆผgf \sim g iff f(0)=g(0)f(0) = g(0). Verify this is an equivalence relation and describe the equivalence class of f(x)=x2f(x) = x^2.

Solution

  1. 1
    Reflexive: f(0)=f(0)f(0)=f(0). True. Symmetric: if f(0)=g(0)f(0)=g(0) then g(0)=f(0)g(0)=f(0). True. Transitive: if f(0)=g(0)f(0)=g(0) and g(0)=h(0)g(0)=h(0), then f(0)=h(0)f(0)=h(0). True.
  2. 2
    The equivalence class of f(x)=x2f(x)=x^2 (where f(0)=0f(0)=0): all functions gg with g(0)=0g(0)=0, e.g., g(x)=x,x3,sinโกx,5x2+3xg(x)=x, x^3, \sin x, 5x^2+3x.

Answer

[x2]={g:Rโ†’Rโˆฃg(0)=0}[x^2] = \{g : \mathbb{R}\to\mathbb{R} \mid g(0)=0\}
Equivalence classes can be defined on any set. Here, functions are grouped by their value at x=0x=0. The class [x2][x^2] contains all functions that vanish at the origin.

About Equivalence Classes

An equivalence class is the set of all elements that are related to a given element under an equivalence relation โ€” it groups objects that are considered 'the same' in some specified sense.

Learn more about Equivalence Classes โ†’

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