Direct Proof Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Direct Proof.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

A direct proof establishes a statement P⇒QP \Rightarrow Q by assuming PP is true and using logical steps, definitions, and known theorems to arrive at QQ — the most straightforward proof strategy.

Start from what you know (the hypotheses) and chain logical steps forward until you reach what you want to prove β€” no detours, no tricks, just forward reasoning.

Read the full concept explanation β†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: A direct proof assumes the hypothesis PP is true and chains definitions, algebra, and known theorems forward until it reaches the conclusion QQ.

Common stuck point: The procedure for direct proof is the easy part; the trap is secretly assuming the conclusion QQ and reasoning toward the hypothesis. Asking "Can I start from the hypothesis and reach the conclusion using only forward steps, never assuming the conclusion is false?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Can I start from the hypothesis and reach the conclusion using only forward steps, never assuming the conclusion is false?

Worked Examples

Example 1

easy
Prove directly: the sum of an even integer and an odd integer is odd.

Answer

a+b=2(m+n)+1Β isΒ oddβ–‘a+b = 2(m+n)+1 \text{ is odd} \quad \square

First step

1
Let aa be even and bb be odd. By definition, a=2ma = 2m and b=2n+1b = 2n+1 for integers m,nm, n.

Full solution

  1. 2
    Then a+b=2m+2n+1=2(m+n)+1a + b = 2m + 2n + 1 = 2(m+n) + 1.
  2. 3
    Since m+nm+n is an integer, a+b=2(m+n)+1a+b = 2(m+n)+1 is odd by definition.
A direct proof proceeds from the hypothesis (definitions of even and odd) to the conclusion (the sum is odd) by explicit algebraic steps. The form 2k+12k+1 for some integer kk is the definition of odd.

Example 2

medium
Prove directly: for all real xx, (xβˆ’1)(x+1)=x2βˆ’1(x-1)(x+1) = x^2 - 1.

Example 3

medium
Prove directly: if nn is an integer then n2+3n+2n^2 + 3n + 2 is even.

Example 4

medium
Prove directly: if nn is an integer, then 4n2+4n+14n^2 + 4n + 1 is odd.

Example 5

hard
Prove directly: for all positive reals a,ba, b, a2+b2β‰₯2aba^2 + b^2 \ge 2ab.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Prove directly: if x>y>0x > y > 0, then x2>y2x^2 > y^2.

Example 2

medium
Prove directly: for all integers nn, n2+nn^2 + n is even.

Example 3

easy
In a direct proof of 'if nn is even then n2n^2 is even', what do you assume FIRST?

Example 4

easy
Complete: 'To prove nn even β‡’n2\Rightarrow n^2 even, start n=2kn=2k, so n2=n^2 = ___.'

Example 5

easy
In a direct proof of 'if nn is odd then n+1n+1 is even', what is the conclusion you must REACH?

Example 6

easy
Direct proof that the sum of two even integers is even: assume a=2ja=2j and b=2kb=2k. What is a+ba+b?

Example 7

easy
Direct proof that 3∣nβ‡’3∣n23 \mid n \Rightarrow 3 \mid n^2: assume n=3kn=3k. What is n2n^2?

Example 8

easy
Direct proof that 'if x>2x>2 then x2>4x^2>4': from x>2x>2 and x>0x>0, what can you multiply to conclude?

Example 9

easy
Which opening is correct for a direct proof of P⇒QP\Rightarrow Q: (A) 'Assume QQ.' or (B) 'Assume PP.'?

Example 10

easy
Direct proof that the product of two odd integers is odd: assume a=2j+1a=2j+1, b=2k+1b=2k+1. Expand abab.

Example 11

medium
Complete the direct proof that nn odd β‡’n2\Rightarrow n^2 odd: assume n=2k+1n=2k+1, then n2=n^2 = ? Show it is odd.

Example 12

medium
Direct proof: if a∣ba \mid b and b∣cb \mid c then a∣ca \mid c. Set up the definitions and finish.

Example 13

medium
Direct proof that if n=2k+1n=2k+1 then n2βˆ’1n^2-1 is divisible by 88. Complete it.

Example 14

medium
Direct proof that the sum of an even and an odd integer is odd: assume a=2ja=2j, b=2k+1b=2k+1. Finish.

Example 15

medium
Direct proof that if xx and yy are rational then x+yx+y is rational. Set up and conclude.

Example 16

medium
Direct proof: if aa and bb are consecutive integers then a+ba+b is odd. Complete it.

Example 17

medium
Find the flaw in this 'direct proof' that n2n^2 even β‡’n\Rightarrow n even: 'Assume nn is even, n=2kn=2k, then n2=4k2n^2=4k^2 is even. Done.' What went wrong?

Example 18

medium
Direct proof that if 5∣n5 \mid n and 5∣m5 \mid m then 5∣(n+m)5 \mid (n+m). Set up and finish.

Example 19

medium
Direct proof that if xx is rational and nonzero then 1x\frac{1}{x} is rational. Complete it.

Example 20

challenge
Direct proof that if nn is an integer then n3βˆ’nn^3-n is divisible by 66. Complete the argument.

Example 21

challenge
Direct proof that the sum of the first nn odd numbers is n2n^2, WITHOUT induction. Give a direct algebraic argument.

Example 22

challenge
Direct proof that if a2+b2=c2a^2+b^2=c^2 with integers and a,ba,b both odd, derive a contradiction-free direct statement about c2β€Šmodβ€Š4c^2 \bmod 4. Complete it.

Example 23

easy
In a direct proof of 'nn is a multiple of 4 β‡’n\Rightarrow n is even', what is the opening assumption?

Example 24

easy
Finish: 'If n=4kn = 4k, then n=2(2k)n = 2(2k), so nn is ____.'

Example 25

easy
Direct proof: if nn is even then 3n3n is even. Set up and finish.

Example 26

easy
Direct proof: for all real xx, x2β‰₯0x^2 \ge 0. Briefly justify.

Example 27

easy
Direct proof: if n=6kn = 6k, then nn is divisible by 3. Finish in one line.

Example 28

medium
Direct proof: if a,ba, b are integers with aa even, then abab is even. Show the steps.

Example 29

medium
Direct proof: if a∣ba \mid b and a∣ca \mid c, then a∣(b+c)a \mid (b+c). Set up and finish.

Example 30

medium
Direct proof: for all reals a,ba, b, (a+b)2β‰₯4ab(a+b)^2 \ge 4ab. Hint: expand.

Example 31

medium
Direct proof: if xx is rational and yy is rational, then xyxy is rational. Complete it.

Example 32

medium
Direct proof that if nn is odd, then n2βˆ’1n^2 - 1 is divisible by 4. Complete it.

Example 33

medium
Direct proof: if a>0a > 0 then a+1/aβ‰₯2a + 1/a \ge 2. (Assume real aa.)

Example 34

medium
Direct proof: if aa and bb are integers with a≑b(modm)a \equiv b \pmod{m}, then a2≑b2(modm)a^2 \equiv b^2 \pmod{m}.

Example 35

hard
Direct proof: if nn is a positive integer, then 1+2+…+n=n(n+1)21 + 2 + \ldots + n = \frac{n(n+1)}{2}. Argue without induction, using Gauss's pairing.

Example 36

hard
Direct proof: if aa is rational and bb is irrational, must a+ba + b be irrational?

Example 37

hard
Direct proof: if nn is an odd integer, then n2≑1(mod8)n^2 \equiv 1 \pmod 8.

Example 38

hard
Direct proof: if ff is even and gg is odd, then fβ‹…gf \cdot g is odd as a function.

Example 39

hard
Direct proof: if a,ba, b are integers and abab is odd, then both aa and bb are odd. (Hint: prove the contrapositive directly via cases.)

Example 40

hard
Direct proof: for any integers a,ba, b, ∣a+bβˆ£β‰€βˆ£a∣+∣b∣|a + b| \le |a| + |b| (triangle inequality on Z\mathbb{Z}).

Example 41

challenge
Direct proof: if nn is an integer, n2≑0n^2 \equiv 0 or 1(mod4)1 \pmod 4.

Example 42

challenge
Direct proof: for all positive reals a,b,ca, b, c, a2+b2+c2β‰₯ab+bc+caa^2 + b^2 + c^2 \ge ab + bc + ca.

Background Knowledge

These ideas may be useful before you work through the harder examples.

logical statementconditionalproof intuition