Differentiation Rules Math Example 3

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Example 3

easy
Differentiate f(x)=x2cosโกxf(x) = x^2 \cos x using the product rule.

Solution

  1. 1
    Let u=x2u = x^2, v=cosโกxv = \cos x, so uโ€ฒ=2xu' = 2x, vโ€ฒ=โˆ’sinโกxv' = -\sin x.
  2. 2
    Product rule: fโ€ฒ(x)=2xcosโกx+x2(โˆ’sinโกx)=2xcosโกxโˆ’x2sinโกxf'(x) = 2x\cos x + x^2(-\sin x) = 2x\cos x - x^2\sin x.

Answer

fโ€ฒ(x)=2xcosโกxโˆ’x2sinโกxf'(x) = 2x\cos x - x^2\sin x
Apply the product rule term by term. The derivative of cosโกx\cos x is โˆ’sinโกx-\sin x, so the second term picks up a negative sign.

About Differentiation Rules

A set of standard formulas for finding derivatives of common function types without using the limit definition each time.

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