Binomial Distribution Math Example 3

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Example 3

medium
A basketball player has a 70%70\% free-throw success rate. In 66 attempts, what is the probability of making exactly 44?

Solution

  1. 1
    (64)=15\binom{6}{4} = 15, p=0.7p = 0.7, 1โˆ’p=0.31 - p = 0.3.
  2. 2
    P(X=4)=15ร—(0.7)4ร—(0.3)2=15ร—0.2401ร—0.09=15ร—0.021609โ‰ˆ0.324P(X = 4) = 15 \times (0.7)^4 \times (0.3)^2 = 15 \times 0.2401 \times 0.09 = 15 \times 0.021609 \approx 0.324.

Answer

P(X=4)โ‰ˆ0.324P(X = 4) \approx 0.324
The binomial model applies because each free throw is independent with a constant probability of success.

About Binomial Distribution

The probability distribution of the number of successes in nn independent yes/no trials, each with probability pp.

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