Binomial Distribution Math Example 1

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Example 1

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A fair coin is flipped 88 times. What is the probability of getting exactly 55 heads?

Solution

  1. 1
    Use the binomial formula: P(X=k)=(nk)pk(1โˆ’p)nโˆ’kP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}, where n=8n = 8, k=5k = 5, p=0.5p = 0.5.
  2. 2
    (85)=8!5!โ‹…3!=56\binom{8}{5} = \frac{8!}{5! \cdot 3!} = 56.
  3. 3
    P(X=5)=56ร—(0.5)5ร—(0.5)3=56ร—(0.5)8=56ร—1256=56256=732P(X = 5) = 56 \times (0.5)^5 \times (0.5)^3 = 56 \times (0.5)^8 = 56 \times \frac{1}{256} = \frac{56}{256} = \frac{7}{32}.

Answer

P(X=5)=732โ‰ˆ0.219P(X = 5) = \frac{7}{32} \approx 0.219
The binomial distribution models the number of successes in nn independent trials, each with the same probability pp of success. The combination (nk)\binom{n}{k} counts the number of ways to arrange kk successes among nn trials.

About Binomial Distribution

The probability distribution of the number of successes in nn independent yes/no trials, each with probability pp.

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