Proton Chemistry Example 2

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Example 2

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The mass of a single proton is approximately 1.673×10241.673 \times 10^{-24} g. How many protons would it take to have a combined mass of 11 g?

Solution

  1. 1
    Each proton has a mass of approximately 1.673×1024g1.673 \times 10^{-24}\,\text{g}. Set up the division: Number of protons=total massmass per proton=1g1.673×1024g\text{Number of protons} = \frac{\text{total mass}}{\text{mass per proton}} = \frac{1\,\text{g}}{1.673 \times 10^{-24}\,\text{g}}
  2. 2
    Perform the calculation: 11.673×1024=10241.6735.98×1023\frac{1}{1.673 \times 10^{-24}} = \frac{10^{24}}{1.673} \approx 5.98 \times 10^{23}
  3. 3
    This number is close to Avogadro's number, which makes sense because hydrogen nuclei are essentially single protons.

Answer

5.98×1023 protons\approx 5.98 \times 10^{23}\text{ protons}
This number is remarkably close to Avogadro's number (6.022×10236.022 \times 10^{23}), which connects the atomic scale to the macroscopic scale we work with in the laboratory.

About Proton

A positively charged subatomic particle found in the nucleus of every atom, with a charge of +1+1 and a mass of approximately 1 atomic mass.

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