pH Chemistry Example 2

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Example 2

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A solution has pH = 9. Calculate [H+][\text{H}^+] and [OHโˆ’][\text{OH}^-].

Solution

  1. 1
    [H+]=10โˆ’pH=10โˆ’9=1.0ร—10โˆ’9โ€‰M[\text{H}^+] = 10^{-\text{pH}} = 10^{-9} = 1.0 \times 10^{-9}\,\text{M}.
  2. 2
    Using Kw=[H+][OHโˆ’]=1.0ร—10โˆ’14K_w = [\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14}:
  3. 3
    [OHโˆ’]=1.0ร—10โˆ’141.0ร—10โˆ’9=1.0ร—10โˆ’5โ€‰M[\text{OH}^-] = \frac{1.0 \times 10^{-14}}{1.0 \times 10^{-9}} = 1.0 \times 10^{-5}\,\text{M}.

Answer

[H+]=10โˆ’9โ€‰M,[OHโˆ’]=10โˆ’5โ€‰M[\text{H}^+] = 10^{-9}\,\text{M},\quad [\text{OH}^-] = 10^{-5}\,\text{M}
The product [H+][OHโˆ’][\text{H}^+][\text{OH}^-] always equals 10โˆ’1410^{-14} at 25ยฐC25ยฐ\text{C}. A basic solution has [OHโˆ’]>[H+][\text{OH}^-] > [\text{H}^+].

About pH

A logarithmic scale ranging from 0 to 14 that quantifies the hydrogen ion concentration [H+][\text{H}^+] in an aqueous solution, where values below 7 indicate acidic.

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