Oxidation Chemistry Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
In the reaction 2Mg+O2→2MgO2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}, identify which species is oxidized.

Solution

  1. 1
    Mg goes from oxidation state 00 (element) to +2+2 (in MgO).
  2. 2
    An increase in oxidation number means the species has lost electrons.
  3. 3
    Therefore, Mg is oxidized: Mg→Mg2++2e−\text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-.

Answer

Mg is oxidized (0 → +2)\text{Mg is oxidized (0 → +2)}
Oxidation is the loss of electrons (OIL RIG: Oxidation Is Loss). The substance that is oxidized serves as the reducing agent because it provides electrons to the other reactant.

About Oxidation

The loss of electrons by an atom, ion, or molecule during a chemical reaction, resulting in an increase in its oxidation state.

Learn more about Oxidation →

More Oxidation Examples

Example 2 medium

In the reaction [formula], write the oxidation and reduction half-reactions.

Example 3 easy

Is iron rusting an example of oxidation? Explain.

Example 4 medium

In the reaction [formula], which substance is oxidized?

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